pytoolconfig

from pytoolconfig import ToolConfig, Field import os # Define your configuration schema class MyToolConfig(ToolConfig): project_name: str = Field(default="my-default-project", help="Name of the project") debug_mode: bool = Field(default=False, help="Enable debug logging") output_dir: str = Field(default="./output", help="Directory for output files") # Simulate a configuration file (e.g., .toolconfig.yaml or pyproject.toml) # In a real scenario, this would be loaded from disk. # For demonstration, we'll manually create a dummy config. # In practice, `from_file`, `from_pyproject`, or `load` would be used. # Example of loading from a dictionary, simulating file content: dummy_config_data = { "tool": { "mytool": { "project_name": os.environ.get("MYTOOL_PROJECT_NAME", "override-from-env"), "debug_mode": True } } } # Load configuration for 'mytool' # The library would typically discover this automatically from `load()` or `from_pyproject()` config = MyToolConfig.load(app_name="mytool", config_data=dummy_config_data) print(f"Project Name: {config.project_name}") print(f"Debug Mode: {config.debug_mode}") print(f"Output Directory: {config.output_dir}") # Demonstrating default value for output_dir which was not in dummy_config_data assert config.output_dir == "./output" # Demonstrating override from dummy_config_data (or environment variable if set) assert config.project_name == (os.environ.get("MYTOOL_PROJECT_NAME", "override-from-env")) assert config.debug_mode is True